crosse wrote: > Well, why don't you post the output of 'free -m'? How much of your RAM is > just being used as cache? Do you have any swap usage? > > What many people don't realize is that the Linux memory model will just start > eating RAM with cache until it needs it for something else, at which time it > will flush some of that cache and give the memory to whatever process needs > it. It's normal. It is not uncommon to see servers with 98% RAM utilization > doing absolutely nothing. Who cares how much RAM you're using? Be worried > when you actually start to see swap usage. > > --seth
Absolutely correct. Linux will try and use up all your ram....this is a good thing. It takes virtually nothing to drop something in memory that's not being used, so as more programs access ram it will cache as much as possible. If something is needed that was just accessed...it can access it very quickly as it's already cached in ram. If your system needs to load something else in ram, you lose nothing in i/o to drop allocated but unused data in ram. http://www.novell.com/coolsolutions/qna/2327.html Q: When I boot up Linux, according to System Monitor, Linux almost immediately starts using 100% of my memory. Is this a bug? A: In general Linux uses as much of ram as it can sensibly get and use. So, at first glance it appears that Windows XP would use memory more efficiently, because more is reported to be free. The truth is that by using all of your memory right from the start and shuffling this around as needed, Linux is much more efficent while Windows does not make use of all the free ram. Linux just uses a fundamentally different, but more efficient memory management system. -------------------- m2f -------------------- Read this topic online here: http://community.zenoss.com/forums/viewtopic.php?p=22037#22037 -------------------- m2f -------------------- _______________________________________________ zenoss-users mailing list [email protected] http://lists.zenoss.org/mailman/listinfo/zenoss-users
