Hi Devs,
This is my thuesday morning stupid question: say I have a socket on
which I send a message, and just after I put a receive on this same
socket in the code. What prevents in libzmq to receive the message I
have just sent ?
Let's raise the question differently, what prevents zmq_proxy to loop
indefinitely since what it receives on socket A, it sends it on socket
B, and vice versa ?
socket A socket B
| ______________________\______________________ |
|/ / \|
| |
|\______________________/______________________/|
| \ |
zmq_proxy(A,B)does not loop on itself like this
Why does it manage to work like this:
socket A socket B
| |
-->|---------------------------------------------->|------------>
| |
| |
<--|<----------------------------------------------|<------------
zmq_proxy(A,B)does what it is expected to do, yeah !
Can I chain: zmq_proxy(A,B); zmq_proxy(B,C), zmq_proxy(C,D), assuming I
start them in different threads ?
Cheers,
Laurent
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