> Note that you'd actually have to verify that the blocks were the same;
> you cannot count on the hash function. If you didn't do this, anyone
> discovering a collision could destroy the colliding blocks/files.
Given that nobody knows how to find sha256 collisions, you'd of course
need to test this code with a weaker hash algorithm.
(It would almost be worth it to have the code panic in the event that a
real sha256 collision was found)
- Bill
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