On Wed, Aug 11, 2010 at 12:57 AM, Peter Taps <ptr...@yahoo.com> wrote:
> Hi Eric, > > Thank you for your help. At least one part is clear now. > > I still am confused about how the system is still functional after one disk > fails. > > Consider my earlier example of 3 disks zpool configured for raidz-1. To > keep it simple let's not consider block sizes. > > Let's say I send a write value "abcdef" to the zpool. > > As the data gets striped, we will have 2 characters per disk. > > disk1 = "ab" + some parity info > disk2 = "cd" + some parity info > disk3 = "ef" + some parity info > > Now, if disk2 fails, I lost "cd." How will I ever recover this? The parity > info may tell me that something is bad but I don't see how my data will get > recovered. > > The only good thing is that any newer data will now be striped over two > disks. > > Perhaps I am missing some fundamental concept about raidz. > > Regards, > Peter > I find the best way to understand how parity works is to think back to your algebra class when you'd have something like 1x +2 = 3 and you could solve for x....it's not EXACTLY like that but solving the parity stuff is similar to solving for x > -- > This message posted from opensolaris.org > _______________________________________________ > zfs-discuss mailing list > zfs-discuss@opensolaris.org > http://mail.opensolaris.org/mailman/listinfo/zfs-discuss >
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