Does anyone know offhand how to get the FULL path of an uploaded file? I am using the standard HTML <input type="file"> within a form inside a DTML document.
Inside my python method, I am getting a ZPublisher.HTTPRequest.FileUpload object. Fine. This stuff wraps the standard python cgi module to give you access to the headers and contents of the file. You can use a FileUpload the same way you would use a file. The problem is: the name of the FileUpload is the leaf name of the file, but not the entire path. Does anyone know how to get the FULL PATHNAME as listed in the input field in the HTML form? I believe Python is being too clever by half and by the time I get my grubby hands on it, the value is gone. The only thing I could come up with was an awful little JavaScript hack where I snag the value from the input field into another "hidden" field using OnChange/OnClick/OnBlur, and grab it later. Any suggestions would be greatly appreciated. Thanks! (Should I repost this question on a python-dev list? hmmmmm) --Craeg _______________________________________________ Zope-Dev maillist - [EMAIL PROTECTED] http://lists.zope.org/mailman/listinfo/zope-dev ** No cross posts or HTML encoding! ** (Related lists - http://lists.zope.org/mailman/listinfo/zope-announce http://lists.zope.org/mailman/listinfo/zope )