On Tuesday 09 March 2004 01:58 pm, Ian Beatty wrote:
> This has to be an easy one.
Good, I'll take it. ;-)
> From within my Python-based product's code, how do I get access to the
> product's directory on the filesystem? os.getcwd() seems to provide the
> working directory of the shell used to launch Zope, at least when running
> in debug mode.
This isn't actually Zope specific; you can easily get the directory a module
lives in using this:
here = os.path.dirname(os.path.abspath(__file__))
The variable "here" will hold a string with an absolute path to the directory
containing the source file for your module (named by __file__). The call to
os.path.abspath() isn't strictly necessary, but protects against future calls
to os.chdir() (though not past calls!) in case the module was loaded from
directory named by a relative directory on sys.path.
You can do this just once at module scope; there's no need to recompute this
each time you need it.
Fred L. Drake, Jr. <fred at zope.com>
PythonLabs at Zope Corporation
Zope-Dev maillist - [EMAIL PROTECTED]
** No cross posts or HTML encoding! **
(Related lists -