the XMLParser.parseString() method  raises an exception

 File "/opt/python-2.4.4/lib/python2.4/unittest.py", line 260, in run
File "/Users/ajung_data/sandboxes/Zope/Zope/lib/python/zope/tal/tests/test_xmlparser.py", line 127, in test_xx
   self._run_check(xml, ())
File "/Users/ajung_data/sandboxes/Zope/Zope/lib/python/zope/tal/tests/test_xmlparser.py", line 106, in _run_check
File "/Users/ajung_data/sandboxes/Zope/Zope/lib/python/zope/tal/xmlparser.py", line 77, in parseString
   self.parser.Parse(s, 1)
UnicodeEncodeError: 'ascii' codec can't encode characters in position 43-48: ordinal not in range(128)

if the string to be parsed is a unicode strings and contains some non-ascii
chars. The following snippet from a private unittest (test_xmlparsers.py)
shows the error.

   def test_xx(self):
xml = unicode('<?xml version="1.0" encoding="utf-8"?><foo>üöä</foo>', 'iso-8859-15')
       self._run_check(xml, ())

I am not sure if this behavior is intentional?! Is the XMLParser supposed
to deal with unicode strings or will it only accept a standard Python string? A workaround inside parseString() would to check for unicode
and convert the string on-the-fly to a Python string with utf-8 encoding.
This is possibly a limitation of the underlying Expat parser...any recommendation how to deal with this issue?


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