I can't believe it, but I didn't have the last comma ({'b':'B', 'bb':'BB'}, )
and that's what was killing me .....agh

BTW, I noticed you are using lists of dictionaries instead of the "standard"
tuple of dictionaries. I don't  know if there are any consequences to doing
this.  Anyway, since yours are lists you should be able to to do this:

class A:
    _properties = [ {'a':'A', 'aa':'AA'}, ]

class B(A):
    _properties = [ {'b':'B', 'bb':'BB'}, ]
    _properties.append(A._properties)

not that it realy matters.

Thanks,

Dan

Andy McKay wrote:

> class A:
>     _properties = [ {'a':'A', 'aa':'AA'}, ]
>
> class B(A):
>     _properties = [ {'b':'B', 'bb':'BB'}, ]
>     _properties = _properties + A._properties
>
> b = B()
> print b._properties
>
> Works for me.
> --
>      Andy McKay, Developer, ActiveState
>      http://www.ActiveState.com
>      Programming for the People
>
> ----- Original Message -----
> From: "Daniel Rusch" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Thursday, August 17, 2000 11:30 AM
> Subject: [Zope] getting base classes's (super class) _properties tuple
>
> > Say I have a fully functional (and more importantly, working) Product
> > will call A.
> >
> > I want to extend this Product's capabilities so I wish to derive another
> >
> > class from it, call it B.
> >
> > No problem,
> >
> > class B(A):
> >     .........
> >
> > now in class B I want to add a new property.
> >
> > Is the a way of getting the base (super) class _properties tuple and
> > just adding the new one to it. Since a tuple is an immutable object I
> > can't do this:
> > _properties=A._properties.append({'id':'RenderStandardHeader',
> > 'type':'int','mode':'w'})
> >
> > Any thoughts ????
> >
> > DR
> >
> >
> > _______________________________________________
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> >
>
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