On Sun, 15 May 2022, arn...@skeeve.com wrote:
It allows you pass pointers of any type without requiring casts:struct foo s[5] = ... memmove(s, & s[1], 4 * sizeof(struct foo)); // shift down 1 The compiler won't complain because any pointer type can be passed to a void* parameter. Otherwise you'd need to cast: memmove((uchar*) s, (uchar*) & s[1], 4 * sizeof(struct foo));
Sure, but you could change it to do the same with char*.
void* has been standard practice (even on Plan 9) for 30+ years. It's not worth changing it now. :-)
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