If you're creating an array you should use parenthesis ().
Robert Jones, BSP, BSCS TTMS Project Interfaces Keesler AFB -----Original Message----- From: activeperl-boun...@listserv.activestate.com [mailto:activeperl-boun...@listserv.activestate.com] On Behalf Of John DePasquale Sent: Wednesday, October 28, 2015 10:13 AM To: activeperl@listserv.ActiveState.com Subject: it's probably just me Hi perl mavens, I'm sure I just don't understand something here, but this one makes zero sense to me: The following snippet prints a 1 local @aList; push @aList, ['first','second','third']; my $nCount = @aList; print "count: $nCount"; BUT, if I add one seemingly irrelevant line ( the second one below ), something crazy happens: local @aList; print "non-existent value: $aList[0][0]\n"; push @aList, ['first','second','third']; my $nCount = @aList; print "count: $nCount"; instead of printing a 1, the last line prints a 2 So the reference in the first print statement to $aList[0][0] appears to have the affect of creating a row in the array. Is this supposed to work this way? Why would such a reference to a non-existent array row result in the creation of an array row? Thank you. - john John DePasquale Chief Executive Officer Paradigm Consulting "Proudly presenting the Vinopedia System" www.vinopedia.us <http://www.vinopedia.us/> 49 Dalby Street Newton, MA 02458 Mobile: 617-610-2424 Fax: 617-600-7326 ________________________________ _______________________________________________ ActivePerl mailing list ActivePerl@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs