Does anyone have any comments on this proof? I don't have the mathematical 
background to tell if it is correct. But it seems related to the idea from 
algorithmic information theory that the worst case complexity for any algorithm 
is equal to the average case for compressed inputs. Then to show that P != NP 
you would show that SAT (specifically 9-SAT) with compressed inputs has 
exponential average case complexity. That is not quite the approach the paper 
takes, probably because compression is not computable.

 -- Matt Mahoney, matmaho...@yahoo.com




________________________________
From: Kaj Sotala <xue...@gmail.com>
To: agi <agi@v2.listbox.com>
Sent: Thu, August 12, 2010 2:18:13 AM
Subject: [agi] Re: [agi] P≠NP

2010/8/12 John G. Rose <johnr...@polyplexic.com>
>
> BTW here is the latest one:
>
> http://www.win.tue.nl/~gwoegi/P-versus-NP/Deolalikar.pdf

See also:

http://www.ugcs.caltech.edu/~stansife/pnp.html - brief summary of the proof

Discussion about whether it's correct:

http://rjlipton.wordpress.com/2010/08/08/a-proof-that-p-is-not-equal-to-np/
http://rjlipton.wordpress.com/2010/08/09/issues-in-the-proof-that-p?np/
http://rjlipton.wordpress.com/2010/08/10/update-on-deolalikars-proof-that-p≠np/
http://rjlipton.wordpress.com/2010/08/11/deolalikar-responds-to-issues-about-his-p≠np-proof/

http://news.ycombinator.com/item?id=1585850

Wiki page summarizing a lot of the discussion, as well as collecting
many of the links above:

http://michaelnielsen.org/polymath1/index.php?title=Deolalikar%27s_P!%3DNP_paper#Does_the_argument_prove_too_much.3F



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