Hello arsperl communauty, I have a single question :
Is it possible through ARSperl to populate a menu that should be the result
of a query ?
Here are the information of my system
1. OS (operating system) version (example: RHEL 4)
Debian Version 4.0
2. Perl version (output from perl -v)
Perl v5.8.8
3. ARSystem version you are connecting to (example: 6.3)
ARSystem 6.00.01
4. API version you compiled against (example: 7.0)
API9
5. ARSperl version (example: 1.91)
1.91
Here is the stucture of the menu
'owner' =>'abc';
'name' => 'AC-LAC';
'refreshCode' => 'open';
'menuType' => 'query';
'menuQuery'=> {
'labelField' => [
8,
536870918,
536870922,
undef,
undef
],
'qualifier' => {
'left' => {
'left' => {
'left' => {
'oper' =>
'rel_op',
'rel_op' =>
{
'left' => {
'fieldId' => 7
},
'right' => {
'dataType' => 'enum',
'value' => 1
},
'oper' => '=='
}
},
'right' => {
'oper' =>
'rel_op',
'rel_op' =>
{
'left' => {
'fieldId' => 536870920
},
'right' => {
'queryCurrent' => 536871238
},
'oper' => '=='
}
},
'oper' => 'and'
},
'right' => {
'left' => {
'oper' =>
'rel_op',
'rel_op' =>
{
'left' => {
'fieldId' => 910000009
},
'right' => {
'dataType' => 'char',
'value' => 'ALL'
},
'oper' => '=='
}
},
'right' => {
'oper' =>
'rel_op',
'rel_op'
=> {
'left' => {
'fieldId' => 910000009
},
'right' => {
'queryCurrent' => 910000009
},
'oper' => '=='
}
},
'oper' => 'or'
},
'oper' => 'and'
},
'right' => {
'left' => {
'oper' => 'rel_op',
'rel_op' => {
'left' =>
{
'fieldId' => 536870919
},
'right'
=> {
'queryCurrent' => 536871048
},
'oper' =>
'=='
}
},
'right' => {
'oper' => 'rel_op',
'rel_op' => {
'left'
=> {
'fieldId' => 536870919
},
'right'
=> {
'dataType' => 'null',
'value' => undef
},
'oper'
=> '=='
}
},
'oper' => 'or'
},
'oper' => 'and'
},
'sortOnLabel' => 1,
'server' => '@',
'valueField' => 536870913,
'schema' => 'CAC'
};
Thank you very much for any help !!
M Chiker
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