I am curently happily running grub 0.96 from a floppy to boot my system which has XP, 2K and Linux on it. All is working quite well. I am going to install grub to the hard disk, but I am just trying to understand how this will affect things.
I understand that Grub writes stage1 to the first 512 bytes of the MBR. That is fine. On my first disk I have W2K and Linux installed, and on disk 2 is Win XP. (Eventually I will be rejumpering disks so that XP will be the first disk and will install Grub in the MBR of that disk.) Anyway, my question is: should I use a simple "setup (hd0)" which installs stage2 right after stage1 or will that overwrite some Microsoft stuff and cause W2K now (XP later) to become unbootable? Where do they put the NT boot loader that Grub chainloads to anyway? Or should I just install stage1 in the first 512 bytes and put stage2 somewhere else with the "install=" command? I think it is safe to replace the first 512 bytes of the MBR with stage1, but I'm not sure what comes after that in a Windows system. Both W2K and XP are NTFS file systems, btw. Maybe I'm making more out of this than I need to, but I want to understand what is going on and I want it to work the first time I do it. And I want to use Grub as my boot loader to boot my systems, and not any MS product. _______________________________________________ Bug-grub mailing list [EMAIL PROTECTED] http://mail.gnu.org/mailman/listinfo/bug-grub
