I know... I worked it out...

<cfset gridlines = ((maxval - minval )/ 10) + 1>

I floor the minval and ceiling the maxval to nearest 10 points....

> -----Original Message-----
> From: Ryan Kime [mailto:[EMAIL PROTECTED]
> Sent: 13 March 2003 15:23
> To: CF-Talk
> Subject: RE: Graphing under MX
>
>
> Adam,
>
> If you are getting your graphing info from a DB, you could get
> the max value
> of the resultset and add to it to X to get the next value of 10 (or 100 or
> 1000). So max value of 121, you would want 130....578 -> 580, etc... That
> would be your "scaleto" value.
>
> Here's a UDF to help you out...
> http://www.cflib.org/udf.cfm?ID=613
>
> Then divide that number by 10 (or 100 or 1000) and that would be your
> gridlines value.
>
>
> Maybe that will get you started.
>
> HTH,
>
> Ryan
>
> -----Original Message-----
> From: Adam Reynolds [mailto:[EMAIL PROTECTED]
> Sent: Thursday, March 13, 2003 5:07 AM
> To: CF-Talk
> Subject: Graphing under MX
>
>
> Hi all,
> I was wondering if somebody had come up with a formula for determining how
> to get cfchart to display a good Y axis?
>
> What I mean is that if you define:
> scalefrom
> scaleto
> gridlines
>
> There should be a way to determine the correct set of points along the y
> axis.
>
> Currently I have gridlines set to 5.
>
> So on a scale range of 20 - 80 you get 5 markes, effectively the quartile
> positions at: 20 35 50 65 80
>
>
> What I ultimately want is not to do it this way I want to determine the
> scale and set it to 20 30 40 50 60 70 80
>
> Its kinda doing my head in. Maybe I am not thinking about this correctly.
>
> Adam
>
>
>
>
> 
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