I want to use a regular _expression_ that
finds any commas that are between quotation marks and
either escapes them or replaces them
Here is an my string.
2003/09/09 14:49:05, "TestUser1",
"/Doc/News/Budgeting,Forecasting & Reporting.doc",
"OK"
As you can see "/Doc/News/Budgeting,Forecasting &
Reporting.doc" has a comma in it. The example above is
a list with 4 items:
2003/09/09 14:49:05
"TestUser1"
"/Doc/News/Budgeting,Forecasting & Reporting.doc"
"OK"
But because the string
("/Doc/News/Budgeting,Forecasting & Reporting.doc")
has
a comma the list len comes back with 5 items which is
wrong. Can you show me how to get around this? Many Thanks
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