Thanks, now if I could just find a job.

----- Original Message -----
From: "Neil H." <[EMAIL PROTECTED]>
To: "CF-Talk" <[EMAIL PROTECTED]>
Sent: Friday, January 11, 2002 5:29 PM
Subject: Re: Times...


> You are the man!
>
> thanks!
>
> Neil
>
> ----- Original Message -----
> From: "Don Vawter" <[EMAIL PROTECTED]>
> To: "CF-Talk" <[EMAIL PROTECTED]>
> Sent: Friday, January 11, 2002 6:54 PM
> Subject: Re: Times...
>
>
> > I have a function that groups date time information by an interval of
> > time(in minutes).
> > The function is : udf_interval_format(@dt datetime,@interval int)
> >
> > so if you wanted to count the number of rows in an interval you would
use:
> >
> > select  utility.dbo.udf_interval_format(yourdatetimefield,2) as
> > yourint,count(*) as ct from yourtable
> > group by utility.dbo.udf_interval_format(yourdatetimefield,2)
> > order by utility.dbo.udf_interval_format(yourdatetimefield,2)
> >
> > which would group data every 2 mins.
> > the output of the function is  hh:mm
> >
> > Here is the function
> >
> > CREATE FUNCTION udf_interval_format(@dt datetime,@interval int)
> > RETURNS varchar(5) AS
> > BEGIN
> > DECLARE @pieces int
> > DECLARE @st varchar(5)
> > DECLARE @hourpart int
> > DECLARE @minpart int
> > set @pieces = (60*datepart(hour,@dt)    +datepart(mi,@dt) )/@interval
> > set @hourpart= @pieces*@interval/60
> > set @minpart =@pieces*@interval -  @hourpart*60
> > set @st= right('00'+cast(@hourpart as
> > varchar),2)+':'+right('00'+cast(@minpart as varchar),2)
> > return @st
> > END
> >
> >
> >
> > ----- Original Message -----
> > From: "Neil H." <[EMAIL PROTECTED]>
> > To: "CF-Talk" <[EMAIL PROTECTED]>
> > Sent: Friday, January 11, 2002 3:54 PM
> > Subject: Times...
> >
> >
> > > Here is a SQL question for yall...
> > >
> > > I have about 3000 rows a day which have a datetime column.  I want to
be
> > > able to graph the number of rows every 2 minutes.  I know it could be
> done
> > > with a lot of looping in CF but what is the best way to tackle this
one?
> > >
> > > Thanks,
> > >
> > > Neil
> > >
> >
> 
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