Ian,

It is a pretty straightforward table in an MSSQL db. Along the lines of thi
s example data (simplified for displaying here):

id..script_name......remoteip.......date.......referer
1.../page1.cfm?id=1..200.36.36.201..2/10/2002..pagez.cfm
2.../page1.cfm?id=2..200.36.36.202..2/10/2002..pageb.cfm
3.../page1.cfm?id=3..200.36.36.203..2/10/2002..pagec.cfm
4.../page1.cfm?id=2..200.36.36.204..2/10/2002..paged.cfm
5.../page1.cfm?id=2..200.36.36.205..2/10/2002..pagee.cfm
6.../page1.cfm?id=4..200.36.36.206..2/10/2002..pagef.cfm
7.../page1.cfm?id=1..200.36.36.207..2/10/2002..pageg.cfm

I need something that will go through and sum the number of times each page
 (the "script_name" field) is hit and then output the results in descending
 order of "popularity." So for the above sample, it would show like this:

/page1.cfm?id=2   3 hits
/page1.cfm?id=1   2 hits
/page1.cfm?id=4   1 hit
/page1.cfm?id=3   1 hit

Thanks for any more help. I'm sure it is simpler than I am making it.

Paul

   



---------- Original Message ----------------------------------
from: "Ian Lurie" <[EMAIL PROTECTED]>
Reply-To: [EMAIL PROTECTED]
date: Sun, 10 Feb 2002 15:00:04 -0800

>Ah, I get it - so the table lists each TIME one page is viewed? Is that
>right?
>
>If you can tell me the database type, and maybe give 2 sample rows of data
,
>it'll be easier to figure out.
>
>We typically handle stuff like this with a storedproc. Here's a query we
>wrote in Access to do what you're describing, only in a store searches
>database. This query pulls the duplicate cities stored in the database, an
d
>returns the city and count:
>
>SELECT First([searches].[city]) AS cityF, Count([searches].[city]) AS
>NumberOfDups
>FROM searches
>WHERE city<>""
>GROUP BY [searches].[city]
>HAVING (((Count(searches.city))>5))
>ORDER BY count([city]) DESC;
>
>Ian
>
>-----Original Message-----
>From: Paul Sinclair [mailto:[EMAIL PROTECTED]]
>Sent: Sunday, February 10, 2002 2:32 PM
>To: CF-Talk
>Subject: RE: SQL ?: Counting number of times for this
>
>
>Ian,
>
>I'm sorry - I don't know what you mean. What is "COUNTER" and "TITLE"? I'm

>assuming you're meaning that these would be fields in the table?
>
>Are you saying I should just select a couple fields from the table and the
n
> output them? That's what I am reading from your post but I am probably mi
s
>sing something. All that does for me is list the records in whatever order

>I selected them but it doesn't count them and then order them by which pag
e
>s were viewed most often.
>
>Thanks for your help - sorry to be thick.
>
>Paul Sinclair
>
>
>
>
>
>
>
>
>---------- Original Message ----------------------------------
>from: "Ian Lurie" <[EMAIL PROTECTED]>
>Reply-To: [EMAIL PROTECTED]
>date: Sun, 10 Feb 2002 13:42:55 -0800
>
>>Assuming you're keeping track of page views in the table you're talking
>>about, just do a query like this:
>>
>>SELECT COUNTER, TITLE
>>FROM TABLE
>>ORDER BY COUNTER DESC
>>
>>Then do a CFOUTPUT with Maxrows = the number of pages you want to show:

>>
>>COUNTER: TITLE
>>COUNTER: TITLE
>>
>>Etc.
>>
>>I may be missing something, but this should do it...
>>
>>-----Original Message-----
>>From: Paul Sinclair [mailto:[EMAIL PROTECTED]]
>>Sent: Sunday, February 10, 2002 1:39 PM
>>To: CF-Talk
>>Subject: SQL ?: Counting number of times for this
>>
>>
>>I'm preparing a simple homebrewed site statistics report for a client. I
>>need to send a cfmail each night showing the top pages viewed in various
>>areas of the site. I'm stumped on how to get the info I need from the db.

>>
>>The table involved is a simple 5 column table. I just need to do a sql qu
e
>ry
>>that will look at the table and figure out which pages were viewed the mo
s
>t
>>times during the previous 24 hours and then output the list of most popul
a
>r
>>pages in descending order of popularity.
>>
>>How do I do the query that will pull that out? I've tried all manner of
>>bizarre combinations with the various aggregate functions. I think I've l
o
>st
>>site of the forest through the trees here.
>>
>>Thanks,
>>Paul Sinclair
>>
>>
>
>
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