Re: println output

[Meikel Brandmeyer]

Hi,

Am 26.12.2008 um 21:43 schrieb Mark Volkmann:

(for [x (range 3)] (println x))

for is not a looping construct. for is a list comprehension.
For side effects as above use doseq.

(doseq [x (range 3)] (println x))

Sincerely
Meikel

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