I guess you want this:

(for [x (range 4) y (range 4)] (str x y))

--
DmitriKo

On Mar 20, 2:05 pm, WoodHacker <ramsa...@comcast.net> wrote:
> When I run the following:
>
>     (for [y (range 4)] (for [x (range 4)] (println x y)))
>
> I get what I expect  -  0 0, 1 0, 2 0, 3 0 etc., but at the end of
> each y loop I also get 4 nils.
>
> ((0 0
> 1 0
> 2 0
> 3 0
> nil nil nil nil) (0 1
> 1 1
> 2 1
> 3 1
> nil nil nil nil) (0 2
>
> What's going on?   And how do I fix it?    Adding a :when to test for
> nil does not seem to do anything.
>
> Bill

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