So, just to be clear, user> (def nil-seq (doall (interleave (repeat 1e5 nil) (repeat 1e5 "whatever"))) ) #'user/nil-seq
user> (time (doall (keep identity nil-seq))) "Elapsed time: 122.485848 msecs" user> (time (doall (remove nil? nil-seq))) "Elapsed time: 149.71484 msecs" --Robert McIntyre On Wed, Nov 17, 2010 at 5:57 AM, Steve Purcell <st...@sanityinc.com> wrote: > Miki <miki.teb...@gmail.com> writes: >> user=> (time (remove nil? (repeat 1000000 nil))) >> "Elapsed time: 0.079312 msecs" >> () >> user=> (time (filter identity (repeat 1000000 nil))) >> "Elapsed time: 0.070249 msecs" >> () >> >> Seems like filter is a bit faster, however YMMV > > > You're not timing the execution, just the construction of a lazy seq: > > user> (time (remove nil? (repeat 1000000 nil))) > "Elapsed time: 0.044 msecs" > () > user> (time (doall (remove nil? (repeat 1000000 nil)))) > "Elapsed time: 772.469 msecs" > () > > -Steve > > > > > >> >> On Nov 16, 4:48 pm, Glen Rubin <rubing...@gmail.com> wrote: >>> What is the fastest way to remove nils from a sequence? >>> >>> I usually use the filter function, but I see there are other functions >>> like remove that should also do the trick. > > -- > You received this message because you are subscribed to the Google > Groups "Clojure" group. > To post to this group, send email to clojure@googlegroups.com > Note that posts from new members are moderated - please be patient with your > first post. > To unsubscribe from this group, send email to > clojure+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/clojure?hl=en -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
