OK I think there is one  thing to be done to make the solution longer:

1. mark the middle ko and then
2. problem should be: B just captured in the middle ko and W is to
move - is the group alive?

See here: 
https://drive.google.com/file/d/1J5Xn4XkOqSsYx0AEBQJj6EL-SjNqNq-o/view?usp=sharing

Assuming x is the top ko, y the middle one etc. the problem is then
equivalent to
F = z && (y || x) with (x = 1, y = 0, z = 0, F is false) and W cannot play at y.

As F is false W has to take the ko at z (x = 1, y = 0, z = 1, F becomes true)
B takes at x (x = 0, y = 0, z = 1 F is false)
W takes at y (x = 0, y = 1, z = 1, F true),
B takes at z (x = 0, y = 1, z = 0, F false) and W is dead as no matter
what W does F remains false (equivalent to ladders failing for W).

--Marcel

On 22 June 2018 at 22:27, Marcel Crasmaru <crasma...@gmail.com> wrote:
> Errata: assuming x is the top ko then the formula encoded by this problem is
>
> z && (y || x)
>
> with x = 1, y = 0, z = 0 and W cannot play at z. Thus W is already
> dead you cannot  make the formula true.
>
> --Marcel
>
> On 22 June 2018 at 22:19, Marcel Crasmaru <crasma...@gmail.com> wrote:
>> The position looks OK is great  - I didn't find any side solutions.
>> Just one observation: I think this encodes x && y || y || z and W is
>> dead already  thus is arguably a easier problem :)
>>
>>  Should make for a great wall poster.
>>
>> On 22 June 2018 at 19:48, John Tromp <john.tr...@gmail.com> wrote:
>>>>>>> at the bottom of my Go page http://tromp.github.io/go.html, which also
>>>>>>> contains an sgf link.
>>>>>>> Direct link to image: http://tromp.github.io/img/WO5lives.png
>>>
>>> Enlarging the board to 29x29 allows for a much better final (I hope)
>>> look, close to my first attempt.
>>>
>>> -John
>>> _______________________________________________
>>> Computer-go mailing list
>>> Computer-go@computer-go.org
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