SZÉPE Viktor writes:
This is the case in Debian releases: squeeze with gcc-4.4$ g++ -o utest u.c u.c: In function ‘int main()’: u.c:5: error: ‘char32_t’ was not declared in this scope u.c:5: error: expected ‘;’ before ‘c’ u.c:6: error: ‘u32string’ is not a member of ‘std’ u.c:6: error: expected ‘;’ before ‘u’ $ g++ -std=c++11 -o utest u.c cc1plus: error: unrecognized command line option "-std=c++11"
Ok, so gcc 4.4 is not going to work. According to https://wiki.debian.org/LTS, squeeze has EOLed a year ago.
wheezy with gcc-4.7 $ g++ -o utest u.c u.c: In function ‘int main()’: u.c:5:4: error: ‘char32_t’ was not declared in this scope u.c:5:13: error: expected ‘;’ before ‘c’ u.c:6:4: error: ‘u32string’ is not a member of ‘std’ u.c:6:19: error: expected ‘;’ before ‘u’ $ g++ -std=c++11 -o utest u.c (no output)
Ok, so with wheezy, and going forward, you should be ok by explicitly using the -std=c++11 compiler flag.
CentOS 5 also comes with gcc 4.4, and CentOS 5 EOLs and the end of this month. But looks like CentOS 6 still uses gcc 4.4, until 2020. That's likely to be problematic, but I'd still like to verify this. It's remotely possible that Red Hat patched in some C++11 support in their build of gcc 4.4.
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