I am not sure, but if you expect Find to return a number, try N(FIND(…)) instead – it converts value into a number.
Howard From: ouch<mailto:ouc...@yahoo.com.INVALID> Sent: Tuesday, April 11, 2017 2:31 AM To: dev@openoffice.apache.org<mailto:dev@openoffice.apache.org> Subject: Possible Formula Bug in Calc? (IsError and Find) I have an array formula that is returning an error of #VALUE when it shouldn't.The formula is below. {=ISERROR(INDEX($'Sales 4-10-2017'.$A$1:$A$1000;SMALL(IF(ISERROR(FIND("Discount";$'Sales 4-10-2017'.$A$1:$A$1000))=0;ROW($'Sales 4-10-2017'.$A$1:$A$1000);"");ROW(A200))))} Digging into it, it seems Find is culprit of the #Value error. However that initial iserror is not catching the error and the error propagates throughout the formula even overriding the error #504 on index caused by the Find function resulting in an invalid row being returned due to the error. I put that final iserror around the index function just to show that something is not right. The formula still returns #VALUE with that on there when it obviously should be returning either true or false regardless of what the rest of the formula is doing. What is strange is if you move the cursor through the formula in the function wizard it gets the expected results of true or false. But on the actual spreadsheet you get that #VALUE error. Oh, I just tried switching out Find for Search and the same thing occurs. So maybe it's a bug in iserror as it's the only constant?
