Re: How to add a character literal to a string without ~ operator?

[Ferhat Kurtulmuş via Digitalmars-d-learn]

On Thursday, 4 April 2024 at 21:23:00 UTC, user1234 wrote:
On Thursday, 4 April 2024 at 19:56:50 UTC, Ferhat Kurtulmuş 
wrote:
[...]

```d
module runnable;

import std.stdio : writeln;
import std.range : chain;

void main() @nogc
{
    auto s = chain("as ", "df ", "j"); // s is lazy
    writeln(s);
}
```

Bad example. The range is indeed a `@nogc` lazy input range but 
`writeln` is not a `@nogc` consumer.

[...]

The input range consumer has to be @nogc as well.

I don't understand your point sorry. I didn't imply anything 
about @nogc. I of course know writeln is not nogc. I just kept 
the example simple.