Re: Why does Nullable implicitly casts when assigning a variable but not when returning from a function?

[Andy Valencia via Digitalmars-d-learn]

On Wednesday, 10 April 2024 at 20:41:56 UTC, Lettever wrote:
```
import std;
Nullable!int func() => 3;
void main() {
    Nullable!int a = 3;
    //works fine
    Nullable!int b = func();
    //does not compile
}

Why make func() Nullable?  It just wants to give you an int, 
right?  Making it a function returning an int fixes this.

Andy