kenton.simpson schrieb:
> Thanks for the Idea. This works
>
> jQuery.fn.reverse = function() {
> this.pushStack(this.get().reverse());
> return this;
> }
>
Nice. That is a better approach then just doing jQuery.fn.reverse =
[].reverse.-- Jörn _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/
