Hello I have an app that displays some database information in a table.
Inside of the html template I am making an edit link that I want to open
another app(page viewLit) while passing a value to it's view. I have added
my code below. My question is I am unsure of how to make this links url
and pass the object data located inside circuit.circuitid along with it. I
haven't been able to find the right way to code this yet and this is just
how I thought that this should be done. If anyone has a better idea I am
open to suggestions.
search_custom.html(code for link)
{% for circuit in filter.qs %}
<tr>
<td class="actions">
<a href="" class ="view-item" title ="View">View</a>
</td>
<td>{{ circuit.circuitid }}</td>
</tr>
{% endfor %}
myapp/myapp/urls.py
urlpatterns = [
path('viewLit/', include('viewLit.urls')),
]
myapp/viewLit/urls.py
urlpatterns=[
path('viewLit/circuitid.id', views.viewLit, name='viewLit'),
]
views.py
def viewLit(request, circuitid):
#display records fields here
return HttpResponse("You are at the viewLit page!")
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