RE: Re: how to write Ajax for a Like button in Django

Vishesh Mangla Mon, 18 May 2020 04:50:14 -0700

Why don’t you use fetch api? Its simple. Once you get the response from the server, you can use InsertAdjacentHtml.

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From: Motaz Hejaze
Sent: 18 May 2020 07:34
To: Django users
Subject: Re: how to write Ajax for a Like button in Django

The button is submitted but without page refresh

On Mon, 18 May 2020, 3:53 am Ahmed Khairy, <ahmed.heshamel...@gmail.com> wrote:

Hi Motaz,
When I added your code it disabled the function of the button nothing happened

On Sunday, May 17, 2020 at 9:30:38 PM UTC-4, Motaz Hejaze wrote:
In your like button form in your templates ,
try this :
<form _onsubmit_="return false">
</form>
 
i don't think you need ajax for this , but if you still need it let us know
On Mon, 18 May 2020, 2:26 am Gabriel Araya Garcia, <gabriela...@gmail.com> wrote:
Hi Ahmed, I was looking for that during several months and I have found examples than not run, and therefore I`ve get one conclution: "It`s not posible to get that functionality in Django". No one could demostrate with example code.
If you find something, please send me the code.

Thanks


Gabriel Araya Garcia
GMI - Desarrollo de Sistemas Informáticos

El dom., 17 may. 2020 a las 20:15, Ahmed Khairy (<ahmed.he...@gmail.com>) escribió:
Hi all,

I need some help writing the ajax for a like button instead of refreshing every time a like is posted

here is the template:

                        <form action="{% url 'score:like_post' post.pk %}" method='POST'>
                            {% csrf_token %}
                    {% if user.is_authenticated %}
                            {% if liked %}
                                <button type='submit' name='post_id' class= "btn btn-danger btn-sm" value="{{post.id}}"> Unlike </button>
                            {% else %}
                                <button type='submit' name='post_id' class= "btn btn-primary btn-sm" value="{{post.id}}"> Like </button>
                            {% endif  %}
                    {% else %}
                    <small><a href="{% url 'login' %}"> Login</a> to Like </small>
                            <strong>{{total_likes}} Likes </strong>
                    {% endif %}
                        </form>

Here is the urls:
    path('like/<int:pk>', LikeView, name='like_post'),

here is the views:
def LikeView(request, pk):
    post = get_object_or_404(Post, id=request.POST.get('post_id'))
    like = False
    if post.likes.filter(id=request.user.id).exists():
        post.likes.remove(request.user)
        like = False

    else:
        post.likes.add(request.user)
        like = True
    return redirect('score:post-detail', pk=pk)

class PostDetailView(DetailView):
    model = Post
    template_name = "post_detail.html"

    def get_context_data(self, *args, **kwargs):
        context = super(PostDetailView, self).get_context_data()

        stuff = get_object_or_404(Post, id=self.kwargs['pk'])
        total_likes = stuff.total_likes()

        liked = False
        if stuff.likes.filter(id=self.request.user.id).exists():
            liked = True

        context["total_likes"] = total_likes
        context["liked"] = liked
        return context

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RE: Re: how to write Ajax for a Like button in Django

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