I think an example may illustrate what I mean a little better. Having a view with an url like the following: http://domain.com/objects/123/rels/?name=zyx&type=xyz
Considering this same view produces hyperlinks (to be sent to it's template) that add extra query parameters to it's URL, like for example: http://domain.com/objects/123/rels/?name=zyx&type=xyz&page=2 Is there a simpler way to achieve this than reading the parsed parameters from the "request" object, reconstructing the original URL, and finally adding the extra parameter? thanks, Filipe On Aug 2, 12:20 pm, Filipe Correia <[EMAIL PROTECTED]> wrote: > Hi, > > I'm struggling with an issue similar to the one presented on this > thread:http://groups.google.com/group/django-users/browse_frm/thread/536c0a7... > > In a view, getting the various elements that compose the current URL's > query string is easy, one only needs to use the "request" object: > > request.GET['name'] > > however, in my case I would like to preserve the current querystring, > whichever it is, replacing (or adding) only the value for a certain > variable (say, the value for "page"). So I would be reading the parsed > query string only to compose it again with very little change. > > Is there a more elegant way to do this? > > thanks in advance, > Filipe Correia --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
