I have spent hours looking in the docs and one this list for an answer to this problem:
I have a model that has, for example, 20 fields. On my site's homepage, where I'd like to offer a preview version of the object, I'd need to retrieve only say, half of those fields to be displayed. My dilemma is whether to simply use a Model.objects.all() query and ignore the unnecessary data in the template, or find a more efficient way to call only the data I need. Perhaps my model design is flawed and I should separate out the data that is not common to the list and detail version of the content, or perhaps I should have a model method that returns only the data fields I need, etc. Forgive me, as I'm very new to this, but I'm stumped. Any suggestions would be gratefully received. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
