I am assuming that you already have an idea of how your datastring will look
like, and what data it is containing... I am considering *"music artist 32L
2L 100 100"* as input data
so here is a example...
L1 = "music artist 32L 2L 100 100".encode("hex")
> L2 = zlib.compress(L1)
> L3 = L2.encode("hex")
> print L3
>
L3 can now be taken as URI referencing string.. which in this special case
is
'789c35c5c10d00200c02c095102aa4f3e8fe336862fcdc7967466e8bf00853ee28454862adfb7308c2ff00401d0b64'
and reverse algo for this is also as easy
D1=789c35c5c10d00200c02c095102aa4f3e8fe336862fcdc7967466e8bf00853ee28454862adfb7308c2ff00401d0b64'.decode("hex")
> D2 = zlib.decompress(D1)
> D3 = D2.decode("hex")
>
you will get your "music artist 32L 2L 100 100" back
And your URL will not send further a psuedo encoded number which is ugly
enough for non-developers :D
you are free to choose encoding, and can nest them in multiple algos to make
the thing more complex
greetings,
Puneet
On Tue, Jan 27, 2009 at 4:48 PM, felix <crucialfe...@gmail.com> wrote:
>
> there is some hashing function or combination of URL encoding that can do
> this :
>
>
> given some parameters :
>
> 'music' 'artist' 32L 2L 100 100
> ( artist id 32, 2nd picture, dimensions 100 x 100 )
>
> I wish to generate a fake filename eg:
>
> tartan_ba6e5e06e794f1368ed3ec20b4594eec.png
>
> and then be able to reverse that filename back into the original parameters
> when needed.
>
> so its either hashing, or compressing the string (to use the most of the
> allowable chars a-zA-Z0-9_ ) or something
>
> hints or pointers anyone ?
> thanks
>
>
>
> http://crucial-systems.com
>
>
> >
>
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