Hello fish terminal team!
I have a quick question about a script I am trying to build.
Based on this stackoverflow question,
http://stackoverflow.com/questions/1583219/awk-sed-how-to-do-a-recursive-find-replace-of-a-string
I am building the following fn:
function recursive_replace
set arg_count (count $argv)
if [ $arg_count != 2 ]
echo "expecting two arguments."
return
end
echo replacing $argv[1]
echo replacing $argv[2]
find . -type f -print0 | xargs -0 sed -i 's/$argv[1]/$argv[2]/g'
end
However I feel like based on the way fish is structured, perhaps I am
approaching the problem wrong. The above fn doesn't work, because $argv[1]
isn't being textually replaced by it's value when the find command is
executed.
Can someone suggest how I can get this to work? I'm either missing
something in the documentation, or completely clueless how fish is
envisioned to be used.
Thanks!! :)
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