Am 19.05.23 um 21:14 schrieb J. Gareth Moreton via fpc-devel:
So I need to ask... should the check for a divisor of -1 still be
performed?
Yes. This is the result of "down sizing" a division. In case of
longint(int64 div int64) can be converted only into longint(int64) div
longint(int64) if this check is carried out. longint($80000000 div
$ffffffff) must silently result in $8000000 in this case.
The case of doing "min_int div -1", even with
unsigned-to-signed typecasting, seems very contrived and the programmer
should expect problems if "min_int" and "-1" appear as the operands. Is
there a specific example where this implicit check is absolutely
necessary? As others have pointed out, silently returning "min_int" as
the answer seems more unexpected (granted this is just the behaviour of
an optimisation that converts the nodes equating to "x div -1" to "-x",
and Intel's NEG instruction doesn't return an error if min_int is its
input operand, but I can't be sure if the same applies to non-Intel
processors and their equivalent instructions).
Kit
On 17/05/2023 09:51, J. Gareth Moreton via fpc-devel wrote:
Logically yes, but using 16-bit as an example, min_int is -32,768, and
signed 16-bit integers range from -32,768 to 32,767. So -32,768 ÷ -1 =
32,768, which is out of range. This is where the problem lies.
Internally, negation involves inverting all of the bits and then
adding 1 (essentially how you subtract a number using two's
complement), so min_int, which is 1000000000000000, becomes
0111111111111111 and then, after incrementing, 1000000000000000, which
is min_int again.
Kit
On 16/05/2023 13:13, Jean SUZINEAU via fpc-devel wrote:
Le 16/05/2023 à 01:47, Stefan Glienke via fpc-devel a écrit :
min_int div -1
"min_int div -1" should give "- min_int" ?
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