https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=277612
Benjamin Takacs <nimaje+...@bureaucracy.de> changed:
What |Removed |Added
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CC| |nimaje+...@bureaucracy.de
--- Comment #1 from Benjamin Takacs <nimaje+...@bureaucracy.de> ---
There is no such thing as a "negative nan", just some nan representation where
the signbit is set and some where it is not, but that should be just a nan for
every purpose. I would say not printing a sign there is clearer, as nobody can
be confused that something like a "negative nan" exists. And that sign =
'\0'; in line 788 seems to be an explicite design desicion to do that to me.
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