I would use mri_label2vol to map your manual labels into the conformed
space (using mri_label2vol) (and assuming that your native space has
voxel sizes 1mm or greater). This is just a single step (I did not
quite follow all the steps you have below). No need to run any
registration, just follow the instructions here
http://surfer.nmr.mgh.harvard.edu/fswiki/FsAnat-to-NativeAnat to get the
proper registration file.
doug
On 11/11/14 10:12 AM, Bruce Fischl wrote:
A) I don't think this matter, but Doug can correct me if I'm wrong.
mri_label2vol will do better partial volume correction
B) You can't partial-volume correct the DICE, but you can compare the
volumes after partial-volume corrections.
C) There are references in our Neuron paper on the definition of the
hippocampus (Caviness, Makris, Kennedy papers)
cheers
Bruce
On Tue, 11 Nov 2014, Bernd Merkel wrote:
Dear all !
I know, this has been discussed a lot in the forum, however, I am
still not
sure, whether my analysis pipeline is correct.
I simply want to compare volumes of FS vs. manual segmentation in the
hippocampus and calculate the dice coefficient. So these are my steps:
1. mri_convert T1.mgz T1.nii
2. Register (e.g. with FLIRT) T1.nii to original_mprage.nii (where the
manual segmentation was done), output: registration.matrix
3. mri_extract_label aseg.mgz 17 left_FreeSurfer_HC.nii
mri_extract_label 53 right_FreeSurfer_HC.nii
4. Register left_ & right_FreeSurfer_HC.nii to original_mprage.nii by
using
registration.matrix
5. mri_compute_overlap left_Freesurfer_ HC left_manual_HC
Now here are my questions:
A) I've read that I should use mri_label2vol instead of mri_convert
Is that correct and how would I process that afterwards ?
B) The volumes form aseg.mgz are different (in my case: bigger) to the
aseg.stats because of partial volume correction. Can I use partial
volume
corrected hippocampal masks ?
C) Where can I find information about the segmentation method of the
hippocampus, used in FreeSurfer, especially regarding the HC borders ?
Because otherwise it might be difficult to calculate and interpret dice
coefficients.
Best regards and thanks for any help,
Bernd
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