On Thu, Jan 31, 2002 at 09:53:00PM -0500, Jason Purdy wrote: > This will not work (the . will match the /'s and preface them with > 0's)... try \d instead:
Yeah, you're right -- a hurried mispaste :-/ > $ perl -e '$a="9/9/1973\n";$a=~s/\b(.)\b/0$1/g;print $a;' > 090/090/1973 This is odd, I get, $ perl -e '$a="9/9/1973\n";$a=~s/\b(.)\b/0$1/g;print $a;' 09/09/1973 $ Debian's Perl 5.6.1. That . should indeed match the / AFAICS; I'm not sure why it isn't here. What does everyone else get? > $ perl -e '$a="9/9/1973\n";$a=~s/\b(\d)\b/0$1/g;print $a;' > 09/09/1973 > $ perl -e '$a="9/09/1973\n";$a=~s/\b(\d)\b/0$1/g;print $a;' > 09/09/1973 > > I would use printf's, tho, even tho I love regexps. :) 'Me too :-)' x 2; Paul (whose other post contained the canonical sprintf version) > > Jason > > ----- Original Message ----- > From: "Paul Makepeace" <[EMAIL PROTECTED]> > To: <[EMAIL PROTECTED]> > Sent: Thursday, January 31, 2002 8:47 PM > Subject: Re: substitution question > > > > On Thu, Jan 31, 2002 at 05:41:15PM -0800, Pradeep Sethi wrote: > > > Thanks but I am looking of any regexp substitution. > > > > > > sorry for typo : I need to change 9/9/1973 to 09/09/1973 > > > > How about, > > > > s/\b(.)\b/0$1/g > > > > Paul > > > -- Paul Makepeace ....................................... http://paulm.com/ "If god is blue, then get going!" -- http://paulm.com/toys/surrealism/
