Hasn't anyone noticed that a decimal to binary or whatever conversion
isn't a JAPH by definition, alone because it does anything other than
output the JAPH? With a looser definition it must at least output "Just
another Perl hacker," perhaps on stderr
Daniel Cutter
@_=($_="aaceeehhjklnoprrrsttu", q<)411!**.&#)(#'&$!!"!!>);for$a(map{
'.'x(ord($_)-3*11)}$_[1]=~m,.,g){s,($a)(.),$1,,$b.=$2};$c.="(.{$_})"
for(4,7,4,6);@_=$b=~m,$c,;push@_,"\n";print map{ucfirst}map{$_.$"}@_
Am 16.11.2011 17:57, schrieb Ronald J Kimball:
> On Wed, Nov 16, 2011 at 04:14:57PM +0100, Olof Johansson wrote:
>> On 2011-11-16 09:57 -0500, Ronald J Kimball wrote:
>>> That should be s/0*//, otherwise you'll get the wrong result for numbers
>>> above 2147483647.
>> That should be s/^0*//, otherwise you'll get the wrong result for
>> numbers above 2147483647.
> No, you are wrong. s/0*// is sufficient, because /0*/ will always match at
> the start of the string anyway.
>
> Ronald
