From: Alan Milewczyk Sent: Saturday, June 3, 2017 22:50
Sent: Saturday, June 3, 2017 14:26 I wrote
The question would appear to be why $is_path is true in Linux but not in
Windows. I don't know enough Perl to be able to answer.
Me neither but maybe the reason is that \ is used in Windows to denote a
folder/directory whereas in Linux it is /.
The \ for Windows directories is handled by
# Replace backslashes with _ if not Windows path
$string =~ s/\\/_/g unless $^O eq "MSWin32" && $is_path;
It is complicated, though. In another part of the code there is a variable
sanitize_mode which can have values between 0 and 4 to denote different
treatment for sanitising file and directory names, and I haven't worked out
how that gets set.
--fatfilename seems to be a red herring. It used to remove characters in
$fat_bad = '["*:<>?|]'
so it didn't do anything with /.
Did v2.97 and earlier handle / in filenames in Linux correctly? If it did I
can't see where the present code is different.
_______________________________________________
get_iplayer mailing list
[email protected]
http://lists.infradead.org/mailman/listinfo/get_iplayer
