2008/10/30 C Rodrigues <[EMAIL PROTECTED]>:
> evidenceOfEq :: CAOp a -> (Eq a => b) -> b

isn't that the same as:

  evidenceOfEq :: Eq a => CAOp a -> b -> b


> Neither does it accept data EqConstraint a b = EqConstraint (Eq a => b).  
> Foiled again.

same here:

  data Eq a => EqConstraint a b = EqConstraint b.

although this must be a typo, since it doesn't make any sense to me.
_______________________________________________
Glasgow-haskell-users mailing list
Glasgow-haskell-users@haskell.org
http://www.haskell.org/mailman/listinfo/glasgow-haskell-users

Reply via email to