En op 21 oktober 2002 sprak Gareth McCaughan:
> I'm feeling very dim. What's wrong with the much simpler
>
> sub subst { (my $a=shift) =~ s/\$\d+/eval$&/eg; $a; }You have to replace '$1' by the actual value of $1. If you try that with a regex, $1 is changed. In your case, $1 (and $2, $3 etc.) is undefined. (-ugene -- As programmers, we're not supposed to be trying to find the shortest solution. We're trying to find the *best* solution. -- /\\ark-_|ason |)ominus
