You could do: runKleisli . mconcat . map Kleisli :: Monoid (Kleisli m a b) => [a -> m b] -> a -> m b
Would that work for you? On Tue, Apr 16, 2013 at 8:35 PM, Christopher Howard < christopher.how...@frigidcode.com> wrote: > So, I'm doing something like this > > foldl (>>=) someA list :: Monad m => m a > > where > list :: Monad m => [a -> m a], > someA :: Monad m => m a > > Is there a more concise way to write this? I don't think foldM is what I > want -- or is it? > > -- > frigidcode.com > > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe > >
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