2007/8/14, Aaron Denney <[EMAIL PROTECTED]>: > The problem with foldl is that you can't easily make it polymorphic > because of how the null case is handled. foldl1 and foldr1 are trivial, > true. >
The original "last" fail on empty list, it's far easier to obtain the same semantic with foldl than with foldr, in fact it isn't hard at all to make it polymorphic without hassle (contrary to the foldr case) _if_ you remember that there _is_ a value in Haskell wich belongs to every type. -- Jedaï _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
