Henning Thielemann wrote:
I'll see, if I understand it.do writeArray arr 0 2 x <- readArray arr 0 writeArray arr 0 (x+x)If 'arr' is an STArray, the 'arr' will contain the unevaluated expression "2+2" as zeroth element and with type STUArray it will contain the evaluated "4" ?
Exactly. Put differently, writeArray :: STUArray -> .. is strict in the third argument whereas writeArray :: STArray -> .. is not. Regards, apfelmus _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
