Hi > > Now why isn't pattern matching lazy by default? This seems odd for a > > newbie since everything else is lazy by default.
f ~(x:xs) = rhs f ~[] = rhs' Now guess what f [] does... If you use a where binding then pattern matching is lazy. Thanks Neil _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
