Vimal wrote:
I was surprised to find out that the following piece of code:
length [1..] > 10
isnt lazily evaluated! I wouldnt expect this to be a bug, but
in this case, shouldnt the computation end when the length function
evaluation goes something like:
10 + length [11..]
That's the spirit, but you still need the right integer type for that :)
I mean, Haskell does not magically detect that the 32(64)-bit integer
(10 + length [11..]) :: Int is bigger than 10 :: Int . But by using
peano numbers, the comparison function can detect that, see also
http://article.gmane.org/gmane.comp.lang.haskell.cafe/26329
Regards,
apfelmus
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