Hi
> complex. The input is quite simple (it's a bunch of numbers), the output
> is quite simple (it's a neatly formatted string), but the process in the
> middle is... a mess. I'd like to find a more readable way of doing stuff
> like this. It's not just this specific function; any general hints would
> be good. ;-)
A nice auxiliary would help:
showEqn :: Int -> [Double] -> String
showEqn i vs = ...
where
(add,ans) = (init vs, last vs)
Then you can half the complexity. There are probably a few useful
functions that aren't in the standard libraries (consperse, joinWith
etc) that you could make use of.
You seem to be doing take 8 on the double - what if the double prints
out more information than this as the result of show?
1000000000000000000 could end up a bit smaller.
Thanks
Neil
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