Is this what you are looking for:
mrs = [0] : [1] : zipWith (++) (tail mrs) mrs
then you can get the one you want with:
mrs !! index
given a suitable value for index
It seems I didn't read the question carefully - you want the infinite
list.
You can recover the solution from mrs if you want, but its not very
pretty:
infrs = [(mrs !! n) !! (n-1) | n <- [1..]]
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