You don't need IO. Just need to use the (=~) operator (which can be confusing due to it's polymorphism).
Take a look at http://www.serpentine.com/blog/2007/02/27/a-haskell-regular-expression-tutorial/ for didactive examples. On Nov 8, 2007 4:21 PM, Uwe Schmidt <[EMAIL PROTECTED]> wrote: > Hi all, > > what's the simplest way to check, whether a given string > is a wellformed regular expression? > > In the API there's just a "mkRegex" which does not make > any checks, and the "matchRegex" which throws an exception > when the regex isn't wellformed. > > So do I need the IO monad for checking a regex? > > Uwe > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe > _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
