Should work with glasgow extensions (-fglasgow-exts). - Phil
On Dec 1, 2007 6:43 PM, PR Stanley <[EMAIL PROTECTED]> wrote: > Hi > > type assoc k v = [(k, v)] > > works beautifully and everything makes sense. > > > type Assoc v = (Ord k) => [(k, v)] > > This doesn't work. Is there any wayof defining k as an element of > type Ordinal. I could redefine k by putting Char or Int in its place. > Why can't I be more general? > Thanks, > Paul > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe >
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