On Jan 9, 2008 1:07 AM, Achim Schneider <[EMAIL PROTECTED]> wrote:
> > Beg pardon? Are you referring to the type of y being described with
> > 'b' instead of 'a'?
> >
> Yes.
"(a -> a) -> a" and "(b -> b) -> b" are equivalent.
For some reason ghc uses b instead of a if you are picky about it,
just provide a type signature explicitly.
Prelude> let {y :: (a -> a) -> a ; y f = f $ y f}
Prelude> :t y
y :: (a -> a) -> a
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